---
title: '4. Median of Two Sorted Arrays'
description: Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays
icon: dot
topics:
  - { name: "Array", slug: "array" }
  - { name: "Binary Search", slug: "binary-search" }
  - { name: "Divide and Conquer", slug: "divide-and-conquer" }
issue: "https://github.com/prdlk/leetcode/issues/66"
sidebar:
  label: 'Median of Two Sorted Arrays'
  badge: 'Hard'
---

### Example 1:
- Input: `nums1 = [1,3], nums2 = [2]`
- Output: `2.00000`
- Explanation: merged array = `[1,2,3]` and median is `2`.

### Example 2:
- Input: `nums1 = [1,2], nums2 = [3,4]`
- Output: `2.50000`
- Explanation: merged array = `[1,2,3,4]` and median is `(2 + 3`) / `2 = 2.5`.

### Constraints:

- `nums1.length == m`
- `nums2.length == n`
- `0 <= m <= 1000`
- `0 <= n <= 1000`
- `1 <= m + n <= 2000`
- `-10^6 <= nums1[i], nums2[i] <= 10^6`

## Solution

```py
class Solution:
    def findMedianSortedArrays(self, nums1: list[int], nums2: list[int]) -> float:
```