46. Permutations
Given an array nums of distinct integers, return all the possible permutations. You can return the answer in any order
ArrayExample 1:
- Input:
nums = [1,2,3] - Output:
[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]
Example 2:
- Input:
nums = [0,1] - Output:
[[0,1],[1,0]]
Example 3:
- Input:
nums = [1] - Output:
[[1]]
Constraints:
1 <= nums.length <= 6-10 <= nums[i] <= 10- All the integers of
numsare unique.
Solution
class Solution:
def permute(self, nums: list[int]) -> list[list[int]]:
result, path = [], []
used = [False] * len(nums)
def backtrack():
if len(path) == len(nums):
result.append(path[:])
return
for i in range(len(nums)):
if used[i]:
continue
used[i] = True
path.append(nums[i])
backtrack()
path.pop()
used[i] = False
backtrack()
return result