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230. Kth Smallest Element in a BST

Given the root of a binary search tree, and an integer k, return the k^th smallest value (1-indexed) of all the values of the nodes in the tree

Tree

Example 1:

  • Input: root = [3,1,4,null,2], k = 1
  • Output: 1

Example 2:

  • Input: root = [5,3,6,2,4,null,null,1], k = 3
  • Output: 3

Constraints:

  • The number of nodes in the tree is n.
  • 1 <= k <= n <= 10^4
  • 0 <= Node.val <= 10^4

Approach

Solution

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def kthSmallest(self, root: Optional[TreeNode], k: int) -> int:
        n = 0
        stack = []
        cur = root

        while cur or stack:
            while cur:
                stack.append(cur)
                cur = cur.left

            cur = stack.pop()
            n += 1
            if n == k:
                return cur.val
            cur = cur.right

Explanation

Last updated on September 24, 2026

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