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74. Search a 2D Matrix

You are given an m x n integer matrix matrix with the following two properties:

Array

Example 1:

  • Input: matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 3
  • Output: true

Example 2:

  • Input: matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 13
  • Output: false

Constraints:

  • m == matrix.length
  • n == matrix[i].length
  • 1 <= m, n <= 100
  • -10^4 <= matrix[i][j], target <= 10^4

Approach

Solution

class Solution:
    def searchMatrix(self, matrix: List[List[int]], target: int) -> bool:
        ROWS, COLS = len(matrix), len(matrix[0])

        top, bot = 0, ROWS - 1
        while top <= bot:
            row = (top + bot) // 2
            if target > matrix[row][-1]:
                top = row + 1
            elif target < matrix[row][0]:
                bot = row - 1
            else:
                break

        if not (top <= bot):
            return False

        row = (top + bot) // 2
        l, r = 0, COLS - 1
        while l <= r:
            m = (l + r) // 2
            if target > matrix[row][m]:
                l = m + 1
            elif target < matrix[row][m]:
                r = m - 1
            else:
                return True
        return False

Explanation

Last updated on September 24, 2026

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