64. Minimum Path Sum
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right, which minimizes the sum of all numbers along its path
Example 1:
- Input:
grid = [[1,3,1],[1,5,1],[4,2,1]] - Output:
7 - Explanation: Because the path
1→3→1→1→1minimizes the sum.
Example 2:
- Input:
grid = [[1,2,3],[4,5,6]] - Output:
12
Constraints:
m == grid.lengthn == grid[i].length1 <= m, n <= 2000 <= grid[i][j] <= 200
Solution
class Solution:
def minPathSum(self, grid: list[list[int]]) -> int:
if not grid or not grid[0]:
return 0
m = len(grid)
n = len(grid[0])
dp = [[0 for _ in range(n)] for _ in range(m)]
for c in range(n):
dp[0][c] = dp[0][c - 1] + grid[0][c] if c else grid[0][c]
for r in range(m):
dp[r][0] = dp[r - 1][0] + grid[r][0] if r else grid[r][0]
for r in range(1, m):
for c in range(1, n):
dp[r][c] = min(dp[r - 1][c], dp[r][c - 1]) + grid[r][c]
return dp[-1][-1]